Light wave traveling in air along x-direction is given by E_y=540 sin 10^4(x- ct)Vm^-1. Then, the peak value of magnetic field of wave will be (Given c = 3 x 108 ms^-1)

Question

Accepted Answer

Correct answer: A. (a) E_y = 540 sin x 104(x - ct) Vm-1 E_0 = 540 Vm-1 B_0= E_0C= 5403 10^8=18 10^-7T

$Light wave traveling in air along x-direction is given by E_{y} = 540 sin π \times 1 0^{4} (x - ct) V m^{- 1} . Then, the peak value of magnetic field of wave will be (Given c = 3 x 108 m s^{- 1})$

Solution

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