The electric field part of an electromagnetic wave in a medium is represented by E_x=0; E_y=2.5 NC cos [(2 10^6 radm)t-( 10^-2 rads)x ]; E_z=0. The wave is

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Correct answer: B. (b) E_y=2.5 NC((2 10^6 radm)t-( 10^-2 rads)x) E_z=0 and E_ =0 The wave is moving in the positive direction of x . This is the form E_y=E_0( ωt- kx) =2 10^6 2 πu=2 10^6 ⇒u=10^6 Hz 2 =k ⇒ 2 = 10^-2 ⇒ = 2 10^-2 =2 10^2=200m .

$The electric field part of an electromagnetic wave in a medium is represented by E_{x} = 0; E_{y} = 2.5 \frac{N}{C} cos [(2 π \times 1 0^{6} \frac{rad}{m}) t - (π \times 1 0^{- 2} \frac{rad}{s}) x]; E_{z} = 0 . The wave is$

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