A ball of mass 0.15 kg is dropped from a height 10 m, strikes the ground and rebounds to the same height. The magnitude of impulse imparted to the ball is nearly ( g=10 m/s^2) [NEET 2021]

Question

Accepted Answer

Correct answer: B. (b) We know that, ∣ Impulse |=m | v ∣ where, v=v_2-v_1 Here, v_2 is velocity reaches to the same height, v_1 is velocity just before striking to the ground. For case (1), ball dropped from the 10 m height and strikes to the ground. Now, the velocity of the ball just before striking to the ground is v_1=- 2 gh ⇒v_1=- 2 (10 ) (10 ) ⇒v_1=-10 2 m/s For case (2), ball rebounds to the same height. The velocity with which the ball just reaches to the same height, v_2= 2 gh ⇒v_2= 2 (10 ) (10 ) ⇒v_2=10 2 m/s Now, magnitude of the impulse imparted to the ball, ∣ Impulse ∣=m | v |=0.15 |10 2- (-10 2 ) |=0.15 |2 10 2 |=4.2 kg m/s

$A ball of mass 0.15 kg is dropped from a height 10 m, strikes the ground and rebounds to the same height. The magnitude of impulse imparted to the ball is nearly (g = 10 m / s^{2}) [NEET 2021]$

Solution

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