A body of weight 200 N is suspended from a tree branch through a chain of mass 10 kg. The branch pulls the chain by a force equal to (if g=10 m/s^2 ) :

Question

Accepted Answer

Correct answer: A. (a) To determine the force that the branch pulls on the chain, we need to consider the combined weight of the body and the chain, as this is the total force that the branch must support due to gravity. The weight of the body is given as 200 N. To find the weight of the chain, we use the formula for weight, which is the mass of an object multiplied by the acceleration due to gravity (g). The mass of the chain is given as 10 kg and g=10 m/s^2, so: Weight of the chain = Mass of the chain g =10 kg 10 m/s^2=100 N The total force that the branch must support is the sum of the weight of the body and the weight of the chain: Total force = Weight of the body + Weight of the =200 N+100 N=300 N Therefore, the branch pulls the chain by a force of 300 N, A.

$A body of weight 200 N is suspended from a tree branch through a chain of mass 10 kg. The branch pulls the chain by a force equal to (if g = 10 m / s^{2}) :$

Solution

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