A lorry is moving on a smooth circular path of radius 50 m with a velocity of 20 ms^-1. Then the banking angle of the road is (Acceleration due to gravity =10 ms^-2 )

Question

Accepted Answer

Correct answer: B. (b) Radius of circular path, R=50 m Velocity, V=20 m/s Banking angle of the road, tan ⁡ = V^2 Rg = tan^-1 ⁡ ( 20^250 10 )= tan^-1 ⁡ ( 45 )

$A lorry is moving on a smooth circular path of radius 50 m with a velocity of 20 ms^{- 1} . Then the banking angle of the road is (Acceleration due to gravity = 10 ms^{- 2})$

Solution

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