The resultant of two forces 3P and 2Pis R. If the first force is doubled then the resultant is also doubled. The angle between the two forces is

Question

Accepted Answer

Correct answer: B. (b) R^2=(3 P)^2+(2 P)^2+2×3 P×2 P×cos θ…(i) (2 R)^2=(6 P)^2+(2 P)^2+2×6 P×2 P×cos θ…(ii) by solving (i) and (ii), cos θ=−1/2 ⇒ θ=120°

$The resultant of two forces 3P and 2Pis R. If the first force is doubled then the resultant is also doubled. The angle between the two forces is$

Solution

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