A force is represented by F=ax^2+bt^1/2 Where x= distance and t= time. The dimensions of b^2/a are :

Question

Accepted Answer

Correct answer: A. (a) F=ax^2+bt^1/2 [a ]= [F ] (x^2 )= (M^1 L^-1 T^-2 ) [b ]= [F ] (t^1/2 )= (M^1L^1T^-5/2 ) ( b^2a )= (M^2L^2T^-5 ) (M^1L^-1T^-2 )= (M^1L^3T^-3 )

$A force is represented by F = a x^{2} + b t^{1/2} Where x = distance and t = time. The dimensions of b^{2} / a are :$

Solution

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