The position of a particle is given by r= (i+2j-k ) and momentum p= (3i+4j-2k ). The angular momentum is perpendicular to the

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Correct answer: A. (a) Неге, r=i+2j-k ,p=3i+4j-2k L=r p=(ijk12-134-2)=i(-4+4)+j(-3+2)+k(4-6)=0i -1j-2k L has component along -y axis and -z axis but it has no component along the x axis. The angular momentum L is in yz-plane. i.e., perpendicular to x-axis.

$The position of a particle is given by r = (i + 2 j - k) and momentum p = (3 i + 4 j - 2 k) . The angular momentum is perpendicular to the$

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