Consider two physical quantities A and B related to each other as E= B-x^2 At where E ,x and t have dimensions of energy, length and time respectively. The dimension of AB is

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Correct answer: B. (b) [B ]=L^2 A= x^2 tE= L^2 TML^2T^-2= 1 MT^-1 [ A ]=M^-1T [ AB ]= (L^2M^-1T^1 )

$Consider two physical quantities A and B related to each other as E = \frac{B - x ^{2}}{At} where E, x and t have dimensions of energy, length and time respectively. The dimension of AB is$

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