Two vectors A and B have equal magnitudes. The magnitude of (A+B) is ‘n’ times the magnitude of (A-B) The angle between Aand Bis

Question

Accepted Answer

Correct answer: A. (a) Let magnitude of two vectors Aand B=a (A+B)= a^2+a^2++2a^2 cos and (A-B)= a^2+a^2-2a^2 ( cos(180°- ) ) = a^2+a^2-2a^2 cos and according to the question, (A+B)=n(A-B) or, a^2+a^2+2a^2 cos a^2+a^2-2a^2 cos =n^2 ⇒ a^2(1+1+2 cos )a^2(1+1-2 cos )n^2 ⇒ (1+ cos )(1- cos )=n^2 Using componendo and dividend theorem, we get = cos^-1 ( n^2-1n^2+1 )

$Two vectors A and B have equal magnitudes. The magnitude of (A + B) is ‘n’ times the magnitude of (A - B) The angle between A and B is$

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