MereTeacher

JEE • NEET • FOUNDATION

JEE · NEET Previous Year Question

$Dot product of two mutual perpendicular vector is$

Topic: NEET PYQ

Answer: A. Full step-by-step solution below.

A $0$
B $1$
D $None of these$

Correct answer: A

Solution

(a) The dot product of two vectors is A \cdot B = (A) (B) cos θ For mutually perpendicular vectors, θ = 90^{\circ} And cos 90^{\circ} = 0 Therefore, A \cdot B = 0

More Vectors & Basic Mathematics PYQs

$A force is represented by F = a x^{2} + b t^{1/2} Where x = distance and t = time. The dimensions of b^{2} / a are :$
$A = 3 i^+ 4 j^Find a vector perpendicular to A in the plane of A$
$Given below are two statements : Statement (I) : Planck's constant and angular momentum have same dimensions. Statement (II) : Lin\dots$
$If A = 3 i + j + 2 k and B = 2 i - 2 j + 4 k then value of | A \times B | will be-$
$The position of a particle is given by r = (i + 2 j - k) and momentum p = (3 i + 4 j - 2 k) . The angular momentu\dots$