A solid sphere of mass 2kg is making pure rolling on a horizontal surface with kinetic energy 2240 J. The velocity of centre of mass of the sphere will be ____ms^-1.

Question

Accepted Answer

Correct answer: 40. (40) K E= 12m v^2+ 12I ω^2 2240 = 122(v)^2 + 12 25(2)R^2. ( vR )^2 2 2 4 0=v^2+ 25v^2 ⇒v=4 0 m/s

$A solid sphere of mass 2kg is making pure rolling on a horizontal surface with kinetic energy 2240 J. The velocity of centre of mass of the sphere will be ____m s^{- 1} .$

Solution

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