Two bodies of mass 1 kg and 3 kg have position vectors i+2j+k and‐3 i-2j+k , respectively. The centre of mass of this system has a position vector

Question

Accepted Answer

Correct answer: A. (a): r_1=i+2_j^ ∧+k for M_1=1 kg r_2=-3i-2j+k for M_2=3 kg r_C= m_ir_i m_i ⇒r_C= (1i+2j+1k ) 1+ (-3i-2j+k ) 34 ⇒r_C= (1i+2j+1k ) 1+ (-9i-6j+3k )4 ⇒r_C= -8i-4j+4k4=-2i-j+k .

$Two bodies of mass 1 kg and 3 kg have position vectors i + 2 j + k and‐3 i - 2 j + k, respectively. The centre of mass of this system has a position vector$

Solution

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