A stone of mass 1 kg is tied to a string 2 m long and is rotated at constant speed of 40 m s^-1 in a vertical circle. The ratio of the tension at the top and the bottom is [Take g=10 m s^-2 ]

Question

Accepted Answer

Correct answer: B. (b) : Given, m=1 kg ,L=2 m and v_H=v_B=40 m s^-1 Tension at the top or the highest point, T_H= mv_H^2L- mg= 1 (40 )^22-1 10=790 N Tension at the bottom or the lowest point, T_B= mv_B^2L+ mg= 1 (40 )^22+10=810 N ∴ Ratio of the tension at the top and the bottom T_HT_B= 790 N810 N= 7981

$A stone of mass 1 kg is tied to a string 2 m long and is rotated at constant speed of 40 m s^{- 1} in a vertical circle. The ratio of the tension at the top and the bottom is [Take g = 10 m s^{- 2}]$

Solution

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