A ring and a disc roll on the horizontal surface without slipping with same linear velocity. If both have same mass and total kinetic energy of the ring is 4 J then total kinetic energy of the disc is

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Accepted Answer

Correct answer: A. (a) : Total kinetic energy of the ring when it tolls without slipping, K_ ring=K_T+K_R= 12mv^2+ 12I_r ^2 = 12mv^2+ 12mr^2 v^2r^2 ( ∵1 ,mr^2 andω= vr) =mv^2 But K_ ting=4 (given) ∴ my^2=41 Similariy, K_ dist= 12mv^2+ 12l_d ( ^2 ) = 12m^2+ 12 m^22 v^2r^2 = 34mv^2= 34 4 J=3 J ( ∵I_d= mr^22) (i) (Using (i))

$A ring and a disc roll on the horizontal surface without slipping with same linear velocity. If both have same mass and total kinetic energy of the ring is 4 J then total kinetic energy of the disc is$

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